mirror of
https://github.com/open-compass/opencompass.git
synced 2025-05-30 16:03:24 +08:00
50 lines
1.5 KiB
Python
50 lines
1.5 KiB
Python
# flake8: noqa: E501
|
|
import re
|
|
|
|
|
|
def check_standalization(model_response, prompt_style, type):
|
|
if model_response.startswith(("{\"answer\":")) and model_response.endswith(
|
|
('}')):
|
|
return 0
|
|
else:
|
|
return 1
|
|
|
|
|
|
def check_empty(model_response):
|
|
if model_response == '':
|
|
return 1
|
|
else:
|
|
return 0
|
|
|
|
|
|
def check_repetition(model_response):
|
|
if any(response in model_response for response in [
|
|
'input info: imagine a self-contained',
|
|
"provide the calculation result to four decimal places and a final \"yes\" or \"no\" answer in json format",
|
|
'输入信息:设想一个', '请根据上述信息,给出计算结果(答案保留四位小数)'
|
|
]):
|
|
return 1
|
|
else:
|
|
return 0
|
|
|
|
|
|
def contains_chinese(text):
|
|
chinese_pattern = re.compile(r'[\u4e00-\u9fff]+')
|
|
result = 1 if chinese_pattern.search(text) is not None else 0
|
|
return result
|
|
|
|
|
|
def contains_english(text):
|
|
english_pattern = re.compile(
|
|
r'[A-Za-z]{7,}'
|
|
) # Taking into account 'fake' and 'random' modes, and considering that the shortest occurrence of English characters in an 'answer' is of length 6, therefore detecting lengths of 7 or more.
|
|
result = 1 if english_pattern.search(text) is not None else 0
|
|
|
|
return result
|
|
|
|
|
|
def check_abnormality(preds):
|
|
abnormalities = 'All Yes' if all(pred == 'yes' or pred == '是' for pred in preds) else \
|
|
'All No' if all(pred == 'no' or pred == '否' for pred in preds) else 0
|
|
return abnormalities
|