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131 lines
12 KiB
Python
131 lines
12 KiB
Python
# GONNA BE DEPRECATED, DON'T USE IT
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from opencompass.openicl.icl_prompt_template import PromptTemplate
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from opencompass.openicl.icl_retriever import ZeroRetriever
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from opencompass.openicl.icl_inferencer import AgentInferencer
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from opencompass.openicl.icl_evaluator import CircularEvaluator, AccEvaluator
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from opencompass.datasets import MathBenchDataset, mathbench_postprocess
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from opencompass.utils.text_postprocessors import first_option_postprocess
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PROMPT_EN = {
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'FEWSHOT_INSTRUCTION_CLOZE' : [
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dict(role='HUMAN', prompt='Mark\'s basketball team scores 25 2 pointers, 8 3 pointers and 10 free throws. Their opponents score double the 2 pointers but half the 3 pointers and free throws. What\'s the total number of points scored by both teams added together?'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:def solution():\n mark_pointers_2 = 25 * 2\n mark_pointers_3 = 8 * 3\n mark_free_throws = 10 * 1\n mark_points_scored = mark_pointers_2 + mark_pointers_3 + mark_free_throws\n opponents_pointers_2 = mark_pointers_2 * 2\n opponents_pointers_3 = mark_pointers_3 / 2\n opponents_free_throws = mark_free_throws / 2\n opponents_points_scored = opponents_pointers_2 + opponents_pointers_3 + opponents_free_throws\n total_points_scored = mark_points_scored + opponents_points_scored\n result = total_points_scored\n return result'),
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dict(role='SYSTEM', prompt='Response:210'),
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dict(role='BOT', prompt='Thought: According to the response, I got the answer\nFinalAnswer: 210'),
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dict(role='HUMAN', prompt='Bella has two times as many marbles as frisbees. She also has 20 more frisbees than deck cards. If she buys 2/5 times more of each item, what would be the total number of the items she will have if she currently has 60 marbles?'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:def solution():\n marbles = 60\n num_increased_marbles = marbles * 2 / 5\n num_total_marbles = marbles + num_increased_marbles\n frisbees = marbles / 2\n num_increased_frisbees = frisbees * 2 / 5\n num_total_frisbees = frisbees + num_increased_frisbees\n deck_cards = frisbees - 20\n num_increased_deck_cards = deck_cards * 2 / 5\n num_total_deck_cards = deck_cards + num_increased_deck_cards\n num_total = num_total_marbles + num_total_frisbees + num_total_deck_cards\n result = num_total\n return result'),
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dict(role='SYSTEM', prompt='Response:140'),
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dict(role='BOT', prompt='Thought: According to the response, I got the answer\nFinalAnswer: 140'),
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dict(role='HUMAN', prompt='A group of 4 fruit baskets contains 9 apples, 15 oranges, and 14 bananas in the first three baskets and 2 less of each fruit in the fourth basket. How many fruits are there?'),
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dict(role='BOT', prompt="""Tool:PythonInterpreter\nTool Input:def solution():\n num_fruits_per_first_three_basket = 9 + 15 + 14\n num_fruits_first_three_basket = num_fruits_per_first_three_basket * 3\n num_apple_fourth_basket = 9 - 2\n num_orange_fourth_basket = 15 - 2\n num_banana_fourth_basket = 14 - 2\n num_fruits_fourth_basket = num_apple_fourth_basket + num_orange_fourth_basket + num_banana_fourth_basket\n num_fruits_total = num_fruits_first_three_basket + num_fruits_fourth_basket\n result = num_fruits_total\n return result"""),
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dict(role='SYSTEM', prompt='Response:146'),
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dict(role='BOT', prompt='Thought: According to the response, I got the answer\nFinalAnswer: 146'),
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dict(role='HUMAN', prompt='{question}'),
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],
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'FEWSHOT_INSTRUCTION_CHOICE' : [
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dict(role='HUMAN', prompt='Given point P(-1,4) lies on the graph of the inverse proportionality function $y=\\frac{{k}}{{x}}$ (k≠0), what is the value of k? A. $-\\frac{{1}}{{4}}$ B. $\\frac{{1}}{{4}}$ C. $4$ D. $-4$'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:from sympy import solve, symbols, Ne, Eq\ndef solution():\n k = symbols(\'k\')\n result = solve([Eq(4, k / (-1)), Ne(k, 0)], k, dict=True)\n return result'),
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dict(role='SYSTEM', prompt='Response:{{Eq(k, -4)}}'),
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dict(role='BOT', prompt='Thought: Substituting point P into the function yields the value of k as $-4$\nFinalAnswer: D'),
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dict(role='HUMAN', prompt='The graph of the power function $y=(x)$ passes through the point$ (2, \\dfrac {{1}}{{4}}) $, what is the value of $f(-3)$? A. $\\frac{{1}}{{9}}$ B. $\\frac{{1}}{{8}})=196-x$ C. $\\frac{{2}}{{9}}$ D. $\\frac{{1}}{{4}}$'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:from sympy import *\ndef solution():\n x, y, k = symbols(\'x y k\')\n eq1 = Eq(2**k, Rational(1, 4))\n k_value = solve(eq1, k)[0]\n y = x**k_value\n result = y.subs(x, -3)\n return result'),
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dict(role='SYSTEM', prompt='Response:1/9'),
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dict(role='BOT', prompt='Thought: The functional expression of the power function is $y=x^{{-2}}$. Substituting $x=-3$ yields $y=$\\frac{{1}}{{9}}$\nFinalAnswer: A'),
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dict(role='HUMAN', prompt='If $3 x-y=12$, what is the value of $\\frac{8^{x}}{2^{y}} ?$\nA. The value cannot be determined from the information given.\nB. $2^{12}$\nC. 4\nD. $8^{2}$'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:from sympy import symbols, Eq, solve\n\ndef sloution():\n x, y = symbols(\'x y\')\n equation = Eq(3*x - y, 12)\n\n y_in_terms_of_x = solve(equation, y)[0]\n expression = 8**x / 2**y_in_terms_of_x\n result = expression.simplify()\n return result'),
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dict(role='SYSTEM', prompt='Response:2**12'),
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dict(role='BOT', prompt='Thought: The value of $\\frac{8^{x}}{2^{y}}$ is $2^{12}$\nFinalAnswer: B'),
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dict(role='HUMAN', prompt='{question}'),
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]
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}
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PROMPT_CN = {
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'FEWSHOT_INSTRUCTION_CLOZE' : [
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dict(role='HUMAN', prompt='Mark的篮球队得到25个2分球，8个3分球和10个罚球。他们的对手得到2分球的两倍，但3分球和罚球的一半。两队得分的总和是多少？'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:def solution():\n mark_pointers_2 = 25 * 2\n mark_pointers_3 = 8 * 3\n mark_free_throws = 10 * 1\n mark_points_scored = mark_pointers_2 + mark_pointers_3 + mark_free_throws\n opponents_pointers_2 = mark_pointers_2 * 2\n opponents_pointers_3 = mark_pointers_3 / 2\n opponents_free_throws = mark_free_throws / 2\n opponents_points_scored = opponents_pointers_2 + opponents_pointers_3 + opponents_free_throws\n total_points_scored = mark_points_scored + opponents_points_scored\n result = total_points_scored\n return result'),
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dict(role='SYSTEM', prompt='Response:210'),
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dict(role='BOT', prompt='Thought: 根据回答，我得到了答案\nFinalAnswer: 210'),
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dict(role='HUMAN', prompt='Bella有两倍于飞盘的弹珠。她还比卡片多20个飞盘。如果她买每种物品多2/5，她会有多少总数的物品，如果她现在有60颗弹珠？'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:def solution():\n marbles = 60\n num_increased_marbles = marbles * 2 / 5\n num_total_marbles = marbles + num_increased_marbles\n frisbees = marbles / 2\n num_increased_frisbees = frisbees * 2 / 5\n num_total_frisbees = frisbees + num_increased_frisbees\n deck_cards = frisbees - 20\n num_increased_deck_cards = deck_cards * 2 / 5\n num_total_deck_cards = deck_cards + num_increased_deck_cards\n num_total = num_total_marbles + num_total_frisbees + num_total_deck_cards\n result = num_total\n return result'),
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dict(role='SYSTEM', prompt='Response:140'),
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dict(role='BOT', prompt='Thought: 根据回答，我得到了答案\nFinalAnswer: 140'),
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dict(role='HUMAN', prompt='一个有4个水果篮子，前三个篮子里有9个苹果、15个橙子和14个香蕉，第四个篮子里每种水果都少2个。总共有多少水果？'),
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dict(role='BOT', prompt="""Tool:PythonInterpreter\nTool Input:def solution():\n num_fruits_per_first_three_basket = 9 + 15 + 14\n num_fruits_first_three_basket = num_fruits_per_first_three_basket * 3\n num_apple_fourth_basket = 9 - 2\n num_orange_fourth_basket = 15 - 2\n num_banana_fourth_basket = 14 - 2\n num_fruits_fourth_basket = num_apple_fourth_basket + num_orange_fourth_basket + num_banana_fourth_basket\n num_fruits_total = num_fruits_first_three_basket + num_fruits_fourth_basket\n result = num_fruits_total\n return result"""),
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dict(role='SYSTEM', prompt='Response:146'),
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dict(role='BOT', prompt='Thought: 根据回答，我得到了答案\nFinalAnswer: 146'),
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dict(role='HUMAN', prompt='{question}'),
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],
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'FEWSHOT_INSTRUCTION_CHOICE' : [
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dict(role='HUMAN', prompt='已知点P（-1，4）在反比例函数$y=\\frac{{k}}{{x}}$ (k≠0)的图象上，则k的值是____'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:from sympy import solve, symbols, Ne, Eq\ndef solution():\n k = symbols(\'k\')\n result = solve([Eq(4, k / (-1)), Ne(k, 0)], k, dict=True)\n return result'),
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dict(role='SYSTEM', prompt='Response:{{Eq(k, -4)}}'),
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dict(role='BOT', prompt='Thought: 将点 P 带入函数解出 k 的值为 $-4$\nFinalAnswer: D'),
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dict(role='HUMAN', prompt='幂函数$ y=(x) $的图象经过点$ (2, \\dfrac {{1}}{{4}}) $，则$ f(-3) $的值为 ______ ．'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:from sympy import *\ndef solution():\n x, y, k = symbols(\'x y k\')\n eq1 = Eq(2**k, Rational(1, 4))\n k_value = solve(eq1, k)[0]\n y = x**k_value\n result = y.subs(x, -3)\n return result'),
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dict(role='SYSTEM', prompt='Response:1/9'),
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dict(role='BOT', prompt='Thought: 求出幂函数的函数表达式为 $y=x^{{-2}}$，代入 $x=-3$ 得到 $y=$\\frac{{1}}{{9}}$\nFinalAnswer: A'),
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dict(role='HUMAN', prompt='如果$3 x-y=12$，则$\\frac{8^{x}}{2^{y}}$的值是多少？\nA. 无法从给定的信息中确定值。\nB. $2^{12}$\nC. 4\nD. $8^{2}$'),
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dict(role='BOT', prompt='Tool:PythonInterpreter\nTool Input:from sympy import symbols, Eq, solve\n\ndef sloution():\n x, y = symbols(\'x y\')\n equation = Eq(3*x - y, 12)\n\n y_in_terms_of_x = solve(equation, y)[0]\n expression = 8**x / 2**y_in_terms_of_x\n result = expression.simplify()\n return result'),
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dict(role='SYSTEM', prompt='Response:2**12'),
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dict(role='BOT', prompt='Thought: $\\frac{8^{x}}{2^{y}}$的值是$2^{12}$\nFinalAnswer: B'),
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dict(role='HUMAN', prompt='{question}'),
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]
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}
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mathbench_sets = {
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'college': ['single_choice_cn', 'cloze_en'],
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'high': ['single_choice_cn', 'single_choice_en'],
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'middle': ['single_choice_cn'],
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'primary': ['cloze_cn'],
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'primary_refine': ['refine_cloze_cn']
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}
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# Use circular evaluation or not
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with_circular_eval = True
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mathbench_agent_datasets = []
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for _split in list(mathbench_sets.keys()):
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for _name in mathbench_sets[_split]:
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prompt_example = PROMPT_CN if '_cn' in _name else PROMPT_EN
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mathbench_infer_cfg = dict(
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prompt_template=dict(type=PromptTemplate,
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template=dict(
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round = prompt_example['FEWSHOT_INSTRUCTION_CLOZE'] if 'cloze' in _name else prompt_example['FEWSHOT_INSTRUCTION_CHOICE'])),
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retriever=dict(type=ZeroRetriever),
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inferencer=dict(type=AgentInferencer)
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)
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mathbench_eval_cfg = dict(
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evaluator=dict(type=CircularEvaluator if 'choice' in _name and with_circular_eval else AccEvaluator),
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pred_postprocessor=dict(type=first_option_postprocess, options='ABCD') if 'single_choice' in _name else dict(type=mathbench_postprocess, name=_name))
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mathbench_agent_datasets.append(
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dict(
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abbr='mathbench-' + _split + '-' + _name + '-agent',
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type=MathBenchDataset,
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path=f'./data/mathbench/{_split}',
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name=_name,
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with_circular=with_circular_eval,
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reader_cfg=dict(
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input_columns=['question'],
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output_column='answer'
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),
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infer_cfg=mathbench_infer_cfg,
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eval_cfg=mathbench_eval_cfg,
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))
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