[Sync] Updata dataset cfg for internMath (#837)

Co-authored-by: liuhongwei <liuhongwei@pjlab.org.cn>
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Fengzhe Zhou 2024-01-24 16:30:32 +08:00 committed by GitHub
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from opencompass.openicl.icl_prompt_template import PromptTemplate
from opencompass.openicl.icl_retriever import ZeroRetriever
from opencompass.openicl.icl_inferencer import GenInferencer
from opencompass.openicl.icl_evaluator import AccEvaluator
from opencompass.datasets import GSM8KDataset, gsm8k_postprocess, gsm8k_dataset_postprocess, Gsm8kEvaluator
gsm8k_reader_cfg = dict(input_columns=['question'], output_column='answer')
gsm8k_infer_cfg = dict(
prompt_template=dict(
type=PromptTemplate,
template=dict(
round=[
dict(role='HUMAN', prompt="Question: {question}\nLet's think step by step\nAnswer:")
],
)),
retriever=dict(type=ZeroRetriever),
inferencer=dict(type=GenInferencer, max_out_len=512))
gsm8k_eval_cfg = dict(evaluator=dict(type=Gsm8kEvaluator),
pred_role="BOT",
pred_postprocessor=dict(type=gsm8k_postprocess),
dataset_postprocessor=dict(type=gsm8k_dataset_postprocess))
gsm8k_datasets = [
dict(
abbr='gsm8k',
type=GSM8KDataset,
path='./data/gsm8k',
reader_cfg=gsm8k_reader_cfg,
infer_cfg=gsm8k_infer_cfg,
eval_cfg=gsm8k_eval_cfg)
]

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from opencompass.openicl.icl_prompt_template import PromptTemplate
from opencompass.openicl.icl_retriever import ZeroRetriever
from opencompass.openicl.icl_inferencer import GenInferencer
from opencompass.datasets import MATHDataset, MATHEvaluator, math_postprocess
math_reader_cfg = dict(input_columns=['problem'], output_column='solution')
math_infer_cfg = dict(
prompt_template=dict(
type=PromptTemplate,
template=dict(round=[
dict(
role="HUMAN",
prompt=
"Problem:\nFind the domain of the expression $\\frac{\sqrt{x-2}}{\sqrt{5-x}}$.}\nSolution:"
),
dict(
role="BOT",
prompt=
"The expressions inside each square root must be non-negative. Therefore, $x-2 \ge 0$, so $x\ge2$, and $5 - x \ge 0$, so $x \le 5$. Also, the denominator cannot be equal to zero, so $5-x>0$, which gives $x<5$. Therefore, the domain of the expression is $\\boxed{[2,5)}$.\nFinal Answer: The final answer is $[2,5)$. I hope it is correct.\n"
),
dict(
role="HUMAN",
prompt=
"Problem:\nIf $\det \mathbf{A} = 2$ and $\det \mathbf{B} = 12,$ then find $\det (\mathbf{A} \mathbf{B}).$\nSolution:"
),
dict(
role="BOT",
prompt=
"We have that $\det (\mathbf{A} \mathbf{B}) = (\det \mathbf{A})(\det \mathbf{B}) = (2)(12) = \\boxed{24}.$\nFinal Answer: The final answer is $24$. I hope it is correct.\n"
),
dict(
role="HUMAN",
prompt=
"Problem:\nTerrell usually lifts two 20-pound weights 12 times. If he uses two 15-pound weights instead, how many times must Terrell lift them in order to lift the same total weight?\nSolution:"
),
dict(
role="BOT",
prompt=
"If Terrell lifts two 20-pound weights 12 times, he lifts a total of $2\cdot 12\cdot20=480$ pounds of weight. If he lifts two 15-pound weights instead for $n$ times, he will lift a total of $2\cdot15\cdot n=30n$ pounds of weight. Equating this to 480 pounds, we can solve for $n$: \\begin{align*} 30n&=480\\\\ \Rightarrow\qquad n&=480/30=\\boxed{16} \end{align*}\nFinal Answer: The final answer is $16$. I hope it is correct.\n"
),
dict(
role="HUMAN",
prompt=
"Problem:\nIf the system of equations: \\begin{align*} 6x-4y&=a,\\\\ 6y-9x &=b. \end{align*}has a solution $(x, y)$ where $x$ and $y$ are both nonzero, find $\\frac{a}{b},$ assuming $b$ is nonzero.\nSolution:"
),
dict(
role="BOT",
prompt=
"If we multiply the first equation by $-\\frac{3}{2}$, we obtain $$6y-9x=-\\frac{3}{2}a.$$Since we also know that $6y-9x=b$, we have $$-\\frac{3}{2}a=b\Rightarrow\\frac{a}{b}=\\boxed{-\\frac{2}{3}}.$$\nFinal Answer: The final answer is $-\\frac{2}{3}$. I hope it is correct.\n"
),
dict(role="HUMAN", prompt="Problem:\n{problem}\nSolution:\n"),
])),
retriever=dict(type=ZeroRetriever),
inferencer=dict(type=GenInferencer, max_out_len=512))
math_eval_cfg = dict(
evaluator=dict(type=MATHEvaluator), pred_postprocessor=dict(type=math_postprocess))
math_datasets = [
dict(
type=MATHDataset,
abbr='math',
path='./data/math/math.json',
reader_cfg=math_reader_cfg,
infer_cfg=math_infer_cfg,
eval_cfg=math_eval_cfg)
]

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from opencompass.openicl.icl_prompt_template import PromptTemplate
from opencompass.openicl.icl_retriever import ZeroRetriever
from opencompass.openicl.icl_inferencer import GenInferencer
from opencompass.datasets import MATHInternDataset, MATHInternEvaluator, math_intern_postprocess
math_reader_cfg = dict(input_columns=['problem'], output_column='solution')
math_infer_cfg = dict(
prompt_template=dict(
type=PromptTemplate,
template=dict(round=[
dict(role='HUMAN', prompt="Question: {problem}\nLet's think step by step\nAnswer:")
])),
retriever=dict(type=ZeroRetriever),
inferencer=dict(type=GenInferencer, max_out_len=512))
math_eval_cfg = dict(
evaluator=dict(type=MATHInternEvaluator), pred_postprocessor=dict(type=math_intern_postprocess))
math_datasets = [
dict(
type=MATHInternDataset,
abbr='math',
path='./data/math/math.json',
reader_cfg=math_reader_cfg,
infer_cfg=math_infer_cfg,
eval_cfg=math_eval_cfg)
]

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@ -61,6 +61,7 @@ from .longbench import * # noqa: F401, F403
from .mastermath2024v1 import * # noqa: F401, F403
from .math import * # noqa: F401, F403
from .math401 import * # noqa: F401, F403
from .math_intern import * # noqa: F401, F403
from .mathbench import * # noqa: F401, F403
from .mbpp import * # noqa: F401, F403
from .medbench import * # noqa: F401, F403

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import json
import re
from datasets import Dataset, DatasetDict
from opencompass.openicl.icl_evaluator import BaseEvaluator
from opencompass.registry import (ICL_EVALUATORS, LOAD_DATASET,
TEXT_POSTPROCESSORS)
from .base import BaseDataset
def last_boxed_only_string(string):
idx = string.rfind('\\boxed')
if idx < 0:
idx = string.rfind('\\fbox')
if idx < 0:
return None
i = idx
right_brace_idx = None
num_left_braces_open = 0
while i < len(string):
if string[i] == '{':
num_left_braces_open += 1
if string[i] == '}':
num_left_braces_open -= 1
if num_left_braces_open == 0:
right_brace_idx = i
break
i += 1
if right_brace_idx is None:
retval = None
else:
retval = string[idx:right_brace_idx + 1]
return retval
def remove_boxed(s):
left = '\\boxed{'
try:
assert s[:len(left)] == left
assert s[-1] == '}'
return s[len(left):-1]
except Exception:
return None
def extract_boxed_answer(pred_str, strip_double_curly_brace=False):
boxed_str = last_boxed_only_string(pred_str)
if boxed_str is None:
return None
answer = remove_boxed(boxed_str)
if answer is None:
return None
if strip_double_curly_brace:
match = re.match('^\{(.*)\}$', answer) # noqa: W605
if match:
answer = match.group(1)
return answer
@LOAD_DATASET.register_module()
class MATHInternDataset(BaseDataset):
@staticmethod
def load(path: str):
dataset = DatasetDict()
data = json.load(open(path))
raw_data = []
for i in data.keys():
raw_data.append({
'problem':
data[i]['problem'],
'solution':
extract_boxed_answer(data[i]['solution'])
})
dataset['test'] = Dataset.from_list(raw_data)
dataset['train'] = Dataset.from_list(raw_data)
return dataset
@ICL_EVALUATORS.register_module()
class MATHInternEvaluator(BaseEvaluator):
def score(self, predictions, references):
if len(predictions) != len(references):
return {
'error': 'predictions and references have different '
'length'
}
correct = 0
count = 0
details = []
for i, j in zip(predictions, references):
detail = {'pred': i, 'answer': j, 'correct': False}
count += 1
if is_equiv(i, j):
correct += 1
detail['correct'] = True
details.append(detail)
result = {'accuracy': 100 * correct / count, 'details': details}
return result
@TEXT_POSTPROCESSORS.register_module('math_intern_postprocess')
def math_intern_postprocess(text: str) -> str:
extractor = Extractor()
return extractor.extract_answer(text)
class Extractor:
def extract_matching_bracket(cls, target_str: str):
if not target_str:
return target_str
current_nest_level = 1
for i, ch in enumerate(target_str):
if ch == '{':
current_nest_level += 1
elif ch == '}':
current_nest_level -= 1
if current_nest_level == 0:
break
return target_str[:i]
def clean(cls, target_str: str):
opt = target_str.strip().replace('{{', '{').replace('}}', '}')
if not opt:
return opt
if opt[-1] == '.' or opt[-1] == '':
return opt[:-1]
return opt
def extract_answer(cls, pred: str, extract_last_num=False):
if pred.find('The final answer is ') >= 0:
x = pred[pred.find('The final answer is ') +
len('The final answer is '):]
x = x[1:x.find('$.')]
# print(x)
return cls.clean(x)
if pred.find('\n\nQuestion:') >= 0:
pred = pred.split('\n\nQuestion:')[0]
if pred.find('The answer is'):
pred = pred[pred.find('The answer is') + len('The answer is'):]
return cls.clean(pred)
if pred.find('# Answer') >= 0:
return cls.clean(pred[pred.find('# Answer') + len('# Answer'):])
if pred.find('The answer is:') >= 0:
return cls.clean(pred[pred.find('The answer is:') +
len('The answer is:'):])
if pred.find('####') >= 0:
return cls.clean(pred[pred.find('####') + 4:])
left = '\\boxed{'
if pred.find(left) >= 0:
pred = pred[pred.find(left) + len(left):]
return cls.clean(cls.extract_matching_bracket(pred))
if extract_last_num:
nums = []
opt = ''
def contain_digit(opt):
for ch in opt:
if ch.isdigit():
return True
return False
for ch in pred:
if ch.isdigit() or ch in ' ,.':
opt = opt + ch
else:
if contain_digit(opt):
nums.append(opt)
opt = ''
if contain_digit(opt):
return cls.clean(opt)
if nums:
return cls.clean(nums[-1])
return None
def fix_fracs(string):
substrs = string.split('\\frac')
new_str = substrs[0]
if len(substrs) > 1:
substrs = substrs[1:]
for substr in substrs:
new_str += '\\frac'
if substr[0] == '{':
new_str += substr
else:
try:
assert len(substr) >= 2
except AssertionError:
return string
a = substr[0]
b = substr[1]
if b != '{':
if len(substr) > 2:
post_substr = substr[2:]
new_str += '{' + a + '}{' + b + '}' + post_substr
else:
new_str += '{' + a + '}{' + b + '}'
else:
if len(substr) > 2:
post_substr = substr[2:]
new_str += '{' + a + '}' + b + post_substr
else:
new_str += '{' + a + '}' + b
string = new_str
return string
def fix_a_slash_b(string):
if len(string.split('/')) != 2:
return string
a = string.split('/')[0]
b = string.split('/')[1]
try:
a = int(a)
b = int(b)
assert string == '{}/{}'.format(a, b)
new_string = '\\frac{' + str(a) + '}{' + str(b) + '}'
return new_string
except AssertionError:
return string
def remove_right_units(string):
# "\\text{ " only ever occurs (at least in the val set)
if '\\text{ ' in string:
splits = string.split('\\text{ ')
assert len(splits) == 2
return splits[0]
else:
return string
def fix_sqrt(string):
if '\\sqrt' not in string:
return string
splits = string.split('\\sqrt')
new_string = splits[0]
for split in splits[1:]:
if split[0] != '{':
a = split[0]
new_substr = '\\sqrt{' + a + '}' + split[1:]
else:
new_substr = '\\sqrt' + split
new_string += new_substr
return new_string
def strip_string(string):
# linebreaks
string = string.replace('\n', '')
# remove inverse spaces
string = string.replace('\\!', '')
# replace \\ with \
string = string.replace('\\\\', '\\')
# replace tfrac and dfrac with frac
string = string.replace('tfrac', 'frac')
string = string.replace('dfrac', 'frac')
# remove \left and \right
string = string.replace('\\left', '')
string = string.replace('\\right', '')
# Remove circ (degrees)
string = string.replace('^{\\circ}', '')
string = string.replace('^\\circ', '')
# remove dollar signs
string = string.replace('\\$', '')
# remove units (on the right)
string = remove_right_units(string)
# remove percentage
string = string.replace('\\%', '')
string = string.replace('\%', '') # noqa: W605
string = string.replace(' .', ' 0.')
string = string.replace('{.', '{0.')
# if empty, return empty string
if len(string) == 0:
return string
if string[0] == '.':
string = '0' + string
# to consider: get rid of e.g. "k = " or "q = " at beginning
if len(string.split('=')) == 2:
if len(string.split('=')[0]) <= 2:
string = string.split('=')[1]
# fix sqrt3 --> sqrt{3}
string = fix_sqrt(string)
# remove spaces
string = string.replace(' ', '')
string = fix_fracs(string)
# manually change 0.5 --> \frac{1}{2}
if string == '0.5':
string = '\\frac{1}{2}'
string = fix_a_slash_b(string)
string = string.replace('x \\in', '').strip() # noqa: W605
# a_b == a, a_{b} == a_b for bit conversion
if string.find('_') >= 0:
p = string.split('_')
p[1] = p[1].replace('{', '').replace('}', '')
string = '_'.join(p)
# 10800 == 10,800; we only deal with single number
if string.strip().find(' ') == -1 and string.find('(') == -1:
string = string.replace(',', '')
return string
def is_equiv(str1, str2, verbose=False):
if str1 is None and str2 is None:
# print("WARNING: Both None")
return False
if str1 is None or str2 is None:
return False
try:
ss1 = strip_string(str1)
ss2 = strip_string(str2)
return ss1 == ss2
except Exception:
return str1 == str2

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@ -71,6 +71,7 @@ def first_option_postprocess(text: str, options: str, cushion=True) -> str:
f'答案为\s?([{options}])',
f'答案选\s?([{options}])',
f'选择?\s?([{options}])',
f'故选?\s?([{options}])'
f'只有选?项?\s?([{options}])\s?是?对',
f'只有选?项?\s?([{options}])\s?是?错',
f'只有选?项?\s?([{options}])\s?不?正确',